How to Verify Grate Inlet Capacity for Stainless Steel Linear Drains
Most linear drain specifications size the channel correctly and then stop. Yet on site, a large share of flooding cases involve a channel with ample cross-section paired with a grate that simply cannot pass the water. A linear drain must clear three bottlenecks in series: the grate must let water in, the channel must carry it away, and the downstream must discharge it.
This article deals with the first bottleneck - grate and slot inlet capacity - with a hand calculation, a blockage derating factor and a multi-return-period check, then walks through diagnosing and fixing a real shortfall.
1. Why a big channel still floods
Channel conveyance is an open-channel uniform flow problem governed by cross-section and slope. Grate inlet is an orifice discharge problem governed by open area and head above the grate. Different physics, and the two capacities are frequently mismatched.
A 200 x 200 mm stainless channel may pass 80 L/s by Manning's equation, but if it is capped with an 8% open area cast iron grate, the grate governs. Water never enters the channel - it sheets across the pavement instead.
Engineering criterion: ponding depth is a direct measure of flood risk. Design practice normally limits head above the grate to 20-30 mm under design rainfall. A scheme that only works once water ponds to 50 mm has already failed.
2. Grate inlet capacity: the orifice equation
Water dropping through cover slots into the channel behaves as free discharge through a thin-plate orifice:
- Q - inlet discharge (m³/s)
- μ - discharge coefficient: 0.60-0.62 for sharp-edged slots; 0.68-0.72 for chamfered or formed openings
- A₀ - effective open area (m²), net of cross bars, frame and end caps
- g - 9.81 m/s²
- h - head above the grate (m), i.e. ponding depth on the cover
Calculating effective open area
- w - net slot width (m); for pedestrian safety normally not above 10-12 mm
- L - installed drain length (m)
- η - net length factor accounting for cross bars; with a 10 mm bar every 500 mm, η = (500 − 10) / 500 = 0.98
Catalogue open-area figures are usually nominal - they exclude cross bars, end plates and the shadowing where the cover seats on the channel body. Always recompute from geometry rather than trusting the printed number.
3. Worked example: diagnosing a 12 m run
Site conditions
| Parameter | Value |
|---|---|
| Site | Logistics park loading apron, South China |
| Catchment area F | 1 200 m² = 0.12 ha |
| Surface | Concrete, runoff coefficient ψ = 0.90 |
| Drain type | Stainless slot drain, w = 12 mm, length L = 12 m |
| Allowable head h | 25 mm = 0.025 m |
Step 1 - Design flow at three return periods
Using the published South China storm intensity formula:
With duration t = 10 min, the denominator (10 + 11.259)^0.750 = 21.259^0.750 ≈ 9.903:
| Return period P | lg P | (1 + 0.438 lg P) | q [L/(s·ha)] | Q = ψ·q·F [L/s] |
|---|---|---|---|---|
| P = 3 a (general areas) | 0.477 | 1.209 | 441.7 | 47.7 |
| P = 10 a (important areas) | 1.000 | 1.438 | 525.4 | 56.7 |
| P = 50 a (sunken plazas, basement ramps) | 1.699 | 1.744 | 637.3 | 68.8 |
Between return periods, P=10a is 1.19x P=3a and P=50a is 1.44x P=3a. Moving up one step is not a marginal increase - demand rises by 19% to 44%. Projects sized once at P=3a will flood when a storm exceeds the standard.
Step 2 - Grate inlet capacity (before derating)
That is 61.3 / 12 = 5.11 L/(s·m) per metre, consistent with measured values for mainstream slot drain products (3-5 L/(s·m) at 20-25 mm head).
Step 3 - Apply the blockage derating
A loading apron carries leaves, grit and packaging debris. Taking k = 0.60 for an industrial yard or car park environment:
Step 4 - Compare and diagnose
| Checkpoint | Demand Q [L/s] | Available [L/s] | Verdict |
|---|---|---|---|
| P = 3 a | 47.7 | 36.8 | ✗ short by 10.9 L/s (23%) |
| P = 10 a | 56.7 | 36.8 | ✗ short by 19.9 L/s |
| P = 50 a | 68.8 | 36.8 | ✗ short by 32.0 L/s |
Conclusion: even at the lowest return period P=3a, the 12 m layout fails.
4. Correction: do not buy capacity with ponding depth
Option A - increase head (rejected)
To lift capacity from 36.8 to 47.7 L/s, the pre-derating figure must reach 79.5 L/s. Inverting the orifice equation:
That requires 42 mm of standing water before the drain keeps up - well beyond the 20-30 mm allowance, and it prices flood risk straight into the design. Rejected.
Option B - extend the run (recommended)
Recheck: A₀ = 0.012 × 16 × 0.98 = 0.1882 m², Q = 0.62 × 0.1882 × 0.700 = 81.7 L/s, derated 49.0 L/s ≥ 47.7 L/s - passes at P=3a.
Option C - twin runs plus higher open area (for P=10a and above)
If the client requires a P=10a check (56.7 L/s), a single line cannot fit the available space. Splitting into two parallel runs reduces demand to 28.4 L/s each, giving L = (28.4 / 0.6) / 5.11 = 9.3 m, adopt 10 m per run. Widening the slot from 12 mm to 15 mm (non-pedestrian areas only) adds roughly another 25% per metre.
Recommended design order: fix the allowable head h first (safety constraint) → then the slot width w (safety and entrapment constraint) → finally use length L to make up the flow. Length is the only parameter that scales linearly with no side effects; both head and slot width have hard ceilings.
5. Blockage derating factors
| Environment | Derating k | Notes |
|---|---|---|
| Indoor / covered (car park interior, concourse) | 0.80-0.90 | No leaf litter; dust only |
| General industrial roads, open car parks | 0.60-0.70 | Regular grit and debris |
| Landscaped boulevards under deciduous trees | 0.40-0.50 | Size for the worst season |
| Catering / kitchen / food processing zones | 0.50-0.60 | Grease build-up; pair with a grease trap |
| Curtain wall bases, around roof planting | 0.45-0.55 | Growing medium and dead branches wash in |
6. Three-bottleneck summary
| Checkpoint | Governing equation | Acceptance criteria |
|---|---|---|
| 1. Grate inlet | Q = μ·A₀·√(2gh) | Head h ≤ 20-30 mm; blockage derating applied |
| 2. Channel conveyance | Q = A·(1/n)·R^(2/3)·i^(1/2) | Fill depth ≤ 0.7-0.8; velocity 0.6 to 3-4 m/s |
| 3. Downstream discharge | Sewer hydraulic calculation | Pipe and manhole capacity ≥ upstream inflow |
System capacity is the minimum of the three - a classic barrel effect, where the shortest stave sets the performance.
7. Five common pitfalls
- Checking the channel but not the grate - a well-calculated section capped by an 8% open cover will not accept the water
- Trusting nominal open area - without deducting cross bars and end plates, real effective area runs 15-25% below the brochure figure
- Sizing for a single return period - passing P=3a and then facing 44% more demand at P=50a
- Buying capacity with ponding depth - designing the flood in, rather than out
- Stainless grate on a carbon steel frame - a galvanic couple in wet service; joints rust and expand within two or three years and the cover warps. Use isolating gaskets or all-stainless fixings.
In one line: true linear drain capacity = min(grate inlet, channel conveyance, downstream discharge). Calculate the grate with the orifice equation, always apply blockage derating, and always recheck at the governing return period - only then can you say it will not flood.
Need a drainage capacity check?
Send us the catchment area, surface type, design return period and site layout - we return a calculation sheet with inlet capacity, blockage derating and recommended drain length.
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